You are watching: Which of the following correctly describes an arrhenius acid?

32. A solution suspected of containing copper is analyzed. To recognize the standard curve, the absorbance of five criteria ran

**nlinux.org:**

0.689 mg/L Cu

**Explanation:**

The equation of the best-fit line is:

*y* = 0.6136*x* + 0.0142

Where *y* is the absorbance and also *x* is the concentration in mg/L.

Now using that equation we calculate *x* when *y* is equal to 0.438, 0.434 & 0.439.

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**1) **0.438 = 0.6136*x* + 0.0142

x = 0.691 mg/L

**2) **0.434 = 0.6136*x* + 0.0142

x = 0.684 mg/L

**3) **0.439 = 0.6136*x* + 0.0142

x = 0.692 mg/L

Finally we calculate the mean of the 3 concentrations:

(0.691 + 0.684 + 0.692)/3 = 0.689 mg/LAn aqueous solution of sulfuric acid has actually a composition of 25wt% and a SG of 1.22. Calculate the Volume of the solution that has

**nlinux.org:**** The volume of solution is **

**Explanation:**

**The connection between specific gravity and thickness of a substance is given as:**

Specific gravity of sulfuric acid solution = 1.22

Density of water = 1.00 g/mL

**Putting worths in over equation we get:**

**We are given:**

25% (m/m) sulfuric acid solution. This suggests that 25 g of sulfuric acid is present in 100 g of solution

**Convariation factor:** 1 kg = 1000 g

Mass of solution having actually 254 kg or 245000 g of sulfuric acid is calculated** by making use of unitary method:**

If 25 grams of sulfuric acid is current in 100 g of solution.

So, 245000 grams of sulfuric acid will be existing in =

**To calculate volume of a substance, we use the equation:**

Density of solution = 1.22 g/mL

Mass of Equipment = 980000 g

**Putting values in over equation, we get:**

**Hence, the volume of solution is **

5 0

10 months ago

In glacial erosion by abrasion a glacier

polet <3.4K>

**nlinux.org:**

yes

**Explanation:**

3 0

1 year ago

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